The total angular momentum of the person-merry go round system is constant. Nothing happens to the angular speed when the person steps off.

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## Does angular momentum change on a merry go round?

The total angular momentum of the person-merry go round system is constant. Nothing happens to the angular speed when the person steps off.

**What is merry go round in physics?**

The motion of a merry go round is circular motion. In this motion the merry go round exerts a centripetal force on the person riding it. The more we move away from the center of circular motion the more centripetal force will be applied on the person riding it.

### What is the angular momentum of a rolling body?

Energy conservation can be used to analyze rolling motion since energy is conserved in rolling motion without slipping. The angular momentum of a single particle about a designated origin is the vector product of the position vector in the given coordinate system and the particle’s linear momentum.

**What is the angular velocity of a merry go round?**

The angular velocity of a merry-go-round is 60 °/sec and located 3.5 m from the centre of rotation.

## What is the problem of merry go round?

The merry-go-round is spinning. Therefore, it is a rotational motion problem.

**What is the angular velocity of the merry-go-round?**

We are told the period (T = 5 seconds) so the initial angular velocity is. = 2 /T = 1.257 rad/s. The initial moment-of-inertia is that of the merry-go-round plus that of the child located at the rim.

### What is angular momentum write the expression for angular momentum?

In advanced mathematical terminology, the three-dimensional angular momentum for a point particle is a pseudovector r × p, the cross product of the particle’s position vector r (relative to some origin) and its momentum vector; the latter is p = mv in Newtonian mechanics.

**What is angular momentum derive an expression for the angular momentum of a rotating body?**

The angular momentum of the particle is defined as the moment of momentum about the axis of rotation. ∴ Angular momentum = linear momentum x perpendicular distance from the axis. If ω is the angular velocity of the particle, then the linear velocity v = r ω. ∴ Angular momentum of each particle = (mv)r = (mrω) r = mr2ω.

## What happens to the rotational velocity of a merry go round?

The rotational inertia of the wheel remains unchanged throughout the whole event. But as the child moves in toward the axis of rotation, the rotational inertia of the child decreases, therefore, in order to maintain a constant angular momentum of the system, the angular velocity of the system has to increase.